Optimal. Leaf size=243 \[ \frac{2 (9 B-C) \tan (c+d x) \sec ^3(c+d x)}{63 d \sqrt{a \sec (c+d x)+a}}-\frac{2 (3 B-19 C) \tan (c+d x) \sec ^2(c+d x)}{105 d \sqrt{a \sec (c+d x)+a}}+\frac{\sqrt{2} (B-C) \tan ^{-1}\left (\frac{\sqrt{a} \tan (c+d x)}{\sqrt{2} \sqrt{a \sec (c+d x)+a}}\right )}{\sqrt{a} d}+\frac{2 (93 B-29 C) \tan (c+d x) \sqrt{a \sec (c+d x)+a}}{315 a d}-\frac{4 (111 B-143 C) \tan (c+d x)}{315 d \sqrt{a \sec (c+d x)+a}}+\frac{2 C \tan (c+d x) \sec ^4(c+d x)}{9 d \sqrt{a \sec (c+d x)+a}} \]
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Rubi [A] time = 0.876197, antiderivative size = 243, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 6, integrand size = 42, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {4072, 4021, 4010, 4001, 3795, 203} \[ \frac{2 (9 B-C) \tan (c+d x) \sec ^3(c+d x)}{63 d \sqrt{a \sec (c+d x)+a}}-\frac{2 (3 B-19 C) \tan (c+d x) \sec ^2(c+d x)}{105 d \sqrt{a \sec (c+d x)+a}}+\frac{\sqrt{2} (B-C) \tan ^{-1}\left (\frac{\sqrt{a} \tan (c+d x)}{\sqrt{2} \sqrt{a \sec (c+d x)+a}}\right )}{\sqrt{a} d}+\frac{2 (93 B-29 C) \tan (c+d x) \sqrt{a \sec (c+d x)+a}}{315 a d}-\frac{4 (111 B-143 C) \tan (c+d x)}{315 d \sqrt{a \sec (c+d x)+a}}+\frac{2 C \tan (c+d x) \sec ^4(c+d x)}{9 d \sqrt{a \sec (c+d x)+a}} \]
Antiderivative was successfully verified.
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Rule 4072
Rule 4021
Rule 4010
Rule 4001
Rule 3795
Rule 203
Rubi steps
\begin{align*} \int \frac{\sec ^4(c+d x) \left (B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sqrt{a+a \sec (c+d x)}} \, dx &=\int \frac{\sec ^5(c+d x) (B+C \sec (c+d x))}{\sqrt{a+a \sec (c+d x)}} \, dx\\ &=\frac{2 C \sec ^4(c+d x) \tan (c+d x)}{9 d \sqrt{a+a \sec (c+d x)}}+\frac{2 \int \frac{\sec ^4(c+d x) \left (4 a C+\frac{1}{2} a (9 B-C) \sec (c+d x)\right )}{\sqrt{a+a \sec (c+d x)}} \, dx}{9 a}\\ &=\frac{2 (9 B-C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}+\frac{2 C \sec ^4(c+d x) \tan (c+d x)}{9 d \sqrt{a+a \sec (c+d x)}}+\frac{4 \int \frac{\sec ^3(c+d x) \left (\frac{3}{2} a^2 (9 B-C)-\frac{3}{4} a^2 (3 B-19 C) \sec (c+d x)\right )}{\sqrt{a+a \sec (c+d x)}} \, dx}{63 a^2}\\ &=-\frac{2 (3 B-19 C) \sec ^2(c+d x) \tan (c+d x)}{105 d \sqrt{a+a \sec (c+d x)}}+\frac{2 (9 B-C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}+\frac{2 C \sec ^4(c+d x) \tan (c+d x)}{9 d \sqrt{a+a \sec (c+d x)}}+\frac{8 \int \frac{\sec ^2(c+d x) \left (-\frac{3}{2} a^3 (3 B-19 C)+\frac{3}{8} a^3 (93 B-29 C) \sec (c+d x)\right )}{\sqrt{a+a \sec (c+d x)}} \, dx}{315 a^3}\\ &=-\frac{2 (3 B-19 C) \sec ^2(c+d x) \tan (c+d x)}{105 d \sqrt{a+a \sec (c+d x)}}+\frac{2 (9 B-C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}+\frac{2 C \sec ^4(c+d x) \tan (c+d x)}{9 d \sqrt{a+a \sec (c+d x)}}+\frac{2 (93 B-29 C) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{315 a d}+\frac{16 \int \frac{\sec (c+d x) \left (\frac{3}{16} a^4 (93 B-29 C)-\frac{3}{8} a^4 (111 B-143 C) \sec (c+d x)\right )}{\sqrt{a+a \sec (c+d x)}} \, dx}{945 a^4}\\ &=-\frac{4 (111 B-143 C) \tan (c+d x)}{315 d \sqrt{a+a \sec (c+d x)}}-\frac{2 (3 B-19 C) \sec ^2(c+d x) \tan (c+d x)}{105 d \sqrt{a+a \sec (c+d x)}}+\frac{2 (9 B-C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}+\frac{2 C \sec ^4(c+d x) \tan (c+d x)}{9 d \sqrt{a+a \sec (c+d x)}}+\frac{2 (93 B-29 C) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{315 a d}+(B-C) \int \frac{\sec (c+d x)}{\sqrt{a+a \sec (c+d x)}} \, dx\\ &=-\frac{4 (111 B-143 C) \tan (c+d x)}{315 d \sqrt{a+a \sec (c+d x)}}-\frac{2 (3 B-19 C) \sec ^2(c+d x) \tan (c+d x)}{105 d \sqrt{a+a \sec (c+d x)}}+\frac{2 (9 B-C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}+\frac{2 C \sec ^4(c+d x) \tan (c+d x)}{9 d \sqrt{a+a \sec (c+d x)}}+\frac{2 (93 B-29 C) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{315 a d}-\frac{(2 (B-C)) \operatorname{Subst}\left (\int \frac{1}{2 a+x^2} \, dx,x,-\frac{a \tan (c+d x)}{\sqrt{a+a \sec (c+d x)}}\right )}{d}\\ &=\frac{\sqrt{2} (B-C) \tan ^{-1}\left (\frac{\sqrt{a} \tan (c+d x)}{\sqrt{2} \sqrt{a+a \sec (c+d x)}}\right )}{\sqrt{a} d}-\frac{4 (111 B-143 C) \tan (c+d x)}{315 d \sqrt{a+a \sec (c+d x)}}-\frac{2 (3 B-19 C) \sec ^2(c+d x) \tan (c+d x)}{105 d \sqrt{a+a \sec (c+d x)}}+\frac{2 (9 B-C) \sec ^3(c+d x) \tan (c+d x)}{63 d \sqrt{a+a \sec (c+d x)}}+\frac{2 C \sec ^4(c+d x) \tan (c+d x)}{9 d \sqrt{a+a \sec (c+d x)}}+\frac{2 (93 B-29 C) \sqrt{a+a \sec (c+d x)} \tan (c+d x)}{315 a d}\\ \end{align*}
Mathematica [A] time = 1.17028, size = 183, normalized size = 0.75 \[ \frac{\tan (c+d x) \left (\frac{1}{4} \sqrt{1-\sec (c+d x)} \sec ^4(c+d x) ((918 B-214 C) \cos (c+d x)-8 (69 B-157 C) \cos (2 (c+d x))+186 B \cos (3 (c+d x))-129 B \cos (4 (c+d x))-423 B-58 C \cos (3 (c+d x))+257 C \cos (4 (c+d x))+1279 C)+315 \sqrt{2} (B-C) \tanh ^{-1}\left (\frac{\sqrt{1-\sec (c+d x)}}{\sqrt{2}}\right )\right )}{315 d \sqrt{1-\sec (c+d x)} \sqrt{a (\sec (c+d x)+1)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.43, size = 975, normalized size = 4. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.661966, size = 1211, normalized size = 4.98 \begin{align*} \left [-\frac{315 \, \sqrt{2}{\left ({\left (B - C\right )} a \cos \left (d x + c\right )^{5} +{\left (B - C\right )} a \cos \left (d x + c\right )^{4}\right )} \sqrt{-\frac{1}{a}} \log \left (\frac{2 \, \sqrt{2} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sqrt{-\frac{1}{a}} \cos \left (d x + c\right ) \sin \left (d x + c\right ) + 3 \, \cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right )^{2} + 2 \, \cos \left (d x + c\right ) + 1}\right ) + 4 \,{\left ({\left (129 \, B - 257 \, C\right )} \cos \left (d x + c\right )^{4} -{\left (93 \, B - 29 \, C\right )} \cos \left (d x + c\right )^{3} + 3 \,{\left (3 \, B - 19 \, C\right )} \cos \left (d x + c\right )^{2} - 5 \,{\left (9 \, B - C\right )} \cos \left (d x + c\right ) - 35 \, C\right )} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right )}{630 \,{\left (a d \cos \left (d x + c\right )^{5} + a d \cos \left (d x + c\right )^{4}\right )}}, -\frac{2 \,{\left ({\left (129 \, B - 257 \, C\right )} \cos \left (d x + c\right )^{4} -{\left (93 \, B - 29 \, C\right )} \cos \left (d x + c\right )^{3} + 3 \,{\left (3 \, B - 19 \, C\right )} \cos \left (d x + c\right )^{2} - 5 \,{\left (9 \, B - C\right )} \cos \left (d x + c\right ) - 35 \, C\right )} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \sin \left (d x + c\right ) + \frac{315 \, \sqrt{2}{\left ({\left (B - C\right )} a \cos \left (d x + c\right )^{5} +{\left (B - C\right )} a \cos \left (d x + c\right )^{4}\right )} \arctan \left (\frac{\sqrt{2} \sqrt{\frac{a \cos \left (d x + c\right ) + a}{\cos \left (d x + c\right )}} \cos \left (d x + c\right )}{\sqrt{a} \sin \left (d x + c\right )}\right )}{\sqrt{a}}}{315 \,{\left (a d \cos \left (d x + c\right )^{5} + a d \cos \left (d x + c\right )^{4}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (B + C \sec{\left (c + d x \right )}\right ) \sec ^{5}{\left (c + d x \right )}}{\sqrt{a \left (\sec{\left (c + d x \right )} + 1\right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 9.22317, size = 528, normalized size = 2.17 \begin{align*} \frac{\frac{315 \,{\left (\sqrt{2} B - \sqrt{2} C\right )} \log \left ({\left | -\sqrt{-a} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a} \right |}\right )}{\sqrt{-a} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )} - \frac{2 \,{\left (\frac{315 \, \sqrt{2} C a^{4}}{\mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )} +{\left (420 \, \sqrt{2} B a^{4} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right ) - 840 \, \sqrt{2} C a^{4} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right ) -{\left (756 \, \sqrt{2} B a^{4} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right ) - 1638 \, \sqrt{2} C a^{4} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right ) -{\left (612 \, \sqrt{2} B a^{4} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right ) - 936 \, \sqrt{2} C a^{4} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right ) -{\left (276 \, \sqrt{2} B a^{4} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right ) - 383 \, \sqrt{2} C a^{4} \mathrm{sgn}\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2}\right )} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{{\left (a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - a\right )}^{4} \sqrt{-a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + a}}}{315 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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